A Train After Travelling 150 Km Meets With An Accident . After travelling 3 hours a train meets with an accident due to this it stops for an hour. A train after travelling 50 km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late.
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The speed of the train is? Required time = 450 / 15 = 30 seconds After travelling for 3 0 minutes a train meets with an accident, due to which it has to stop for 4 5 minutes.
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Speed = {54 × (5/18)} m/sec = 15 m/sec. (or original time is $45×4=180$ minutes $=3$ hour). A train meets with an accident and travels at 4/7th of its regular speed hereafter and hence it reaches its destination 36 minutes late. It means it covers 300 km distance in 5 hours.
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Had the accident occurred 360 km further, it would have reached the destination 4 hours late. Therefore distance between a and b $=100+150=250$ km. A train after travelling 150 km meets with an accident and then proceeds at 3/5 of its former speed and arrives at its destination 8 hours late. A train after travelling 150 km meets with an.
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A train after travelling 150 km meets with an accident and proceeds at `3/5`of its former speed and arrives at its destination 8 hours late. Required time = 450 / 15 = 30 seconds What is the total distance traveled by the train?: Two trains 150 miles apart are travelling toward each other. I.e., after travelling $100$ km, $\dfrac{1}{4}$ of.
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A train after travelling 150 km meets with an accident and then proceeds at 3/5 of its former speed and arrives at its destination 8 hours late. What is the total distance travelled by the train? Had the accident occurred 6 0 km later, the train would have reached 3 0 minutes earlier. Had the accident occurred 360 km further,.
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Speed = {54 × (5/18)} m/sec = 15 m/sec. A train after travelling 150 km meets with an accident and then proceeds at 3/5 of its former speed and arrives at its destination 8 hours late. #timeanddistancebyprabhakarsir #careeradhyapana train after travelling 225 km meets with an accident and then proceeds at 4/7 of its former speed and arrives. Let y.
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Had the accident occurred 360 km further, it would have reached the destination 4 hours late. Thus unusual time which is require to complete the journey = 5 × 2 = 10 hours. Let us assume the distance the train has to cover after the accident as $ y $ km and the speed of the train before the accident.
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What is the distance travelled by the train? Due to the accident its speed is also reduced to 3 2 of its former value and the train reaches its destination 1 hour 3 0 minutes late. Then time taken will be. A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed.
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Then time taken will be. A train after travelling 150 km meets with an accident and then proceeds at 3/5 of its former speed and arrives at its destination 8 hours late. After travelling for 3 0 minutes a train meets with an accident, due to which it has to stop for 4 5 minutes. Had the accident occurred 30.
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A train meets with an accident and travels at 4/7th of its regular speed hereafter and hence it reaches its destination 36 minutes late. A train after travelling 50 km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late. Due to the accident its speed is also reduced.
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After this the train moves at 75% speed of its original speed and reaches to destination 4 hours late. Had the accident occurred 6 0 km later, the train would have reached 3 0 minutes earlier. After travelling for 3 0 minutes a train meets with an accident, due to which it has to stop for 4 5 minutes. Let.
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A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late. Had the accident occured 24kms further, it would have reached the destination only 25 minutes late. It means it covers 300 km distance in 5 hours. (a) 960 km (b) 870 km (c).
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Let us assume the distance the train has to cover after the accident as $ y $ km and the speed of the train before the accident is $ x $ km/hr. Had the accident occurred 360 km further, it would have reached the destination 4 hours late. Let s = the normal speed of the train then A train.
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What is the total distance travelled by the train ? A) 36 kmph b) 48 kmph c) 54 kmph d) 58 kmph Had the accident occurred 360 km further, it would have reached the destination 4 hours. Due to the accident its speed is also reduced to 3 2 of its former value and the train reaches its destination 1.
Source: venturebeat.com
#timeanddistancebyprabhakarsir #careeradhyapana train after travelling 150 km meets with an accident and then proceeds at 3/5 of its former speed and arrives. A train after travelling 150 km meets with an accident and proceeds at `3/5`of its former speed and arrives at its destination 8 hours late. Had the accident occurred 360 km further, it would have reached the destination.
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A train after travelling 50kms meets with an accident and then proceeds at 3/4th of its former speed and arrives at its destination 35 minutes late. Required time = 450 / 15 = 30 seconds I.e., after travelling $100$ km, train takes $3$ hour for its journey and therefore covers a distance of $3×50=150$ km. Due to the accident its.
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A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late. (a) 960 km (b) 870 km (c) 840 km (d) 1100 km A train meets with an accident and travels at 4/7th of its regular speed hereafter and hence it reaches its destination.
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Let y be the balance distance to be covered and x be the former speed. I.e., after travelling $100$ km, $\dfrac{1}{4}$ of the original time to cover remaining distance is $45$ minutes. A train 300 m long is running at a speed of 54 km/hr. #timeanddistancebyprabhakarsir #careeradhyapana train after travelling 150 km meets with an accident and then proceeds at.
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Let us assume the distance the train has to cover after the accident as $ y $ km and the speed of the train before the accident is $ x $ km/hr. Due to the accident its speed is also reduced to 3 2 of its former value and the train reaches its destination 1 hour 3 0 minutes late..
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What is the total distance travelled by the train ? It means it covers 300 km distance in 5 hours. A train after travelling 150 km meets with an accident and then proceeds at 3/5 of its former speed and arrives at its destination 8 hours late. The length of journey is I.e., after travelling $100$ km, train takes $3$.
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(or original time is $45×4=180$ minutes $=3$ hour). A train after travelling 150 km meets with an accident and then proceeds at 3/5 of its former speed and arrives at its destination 8 hours late. Had the accident occurred 360 km further, it would have reached the destination 4 hours late. If the accident would occur at 150 km ahead.
Source: caymaneco.org
So the speed of the train after the accident is $ \dfrac{3}{4}x $ km/hr. Thus unusual time which is require to complete the journey = 5 × 2 = 10 hours. After travelling for 3 0 minutes a train meets with an accident, due to which it has to stop for 4 5 minutes. #timeanddistancebyprabhakarsir #careeradhyapana train after travelling 150.
